An 8×10in photo print needs 2,400 × 3,000 pixels at the standard 300 DPI target — 8 × 300 = 2,400px wide, 10 × 300 = 3,000px tall.
See how big your image can print — including at 8×10.
Open Print Size Calculator| DPI | Width (px) | Height (px) |
|---|---|---|
| 72 DPI | 576 | 720 |
| 150 DPI | 1,200 | 1,500 |
| 200 DPI | 1,600 | 2,000 |
| 240 DPI | 1,920 | 2,400 |
| 300 DPI | 2,400 | 3,000 |
| 600 DPI | 4,800 | 6,000 |
The math is direct multiplication: pixels = inches × DPI. For an 8in-wide print at 200 DPI, that's 8 × 200 = 1,600px; at 240 DPI, 8 × 240 = 1,920px — a common source resolution for images pulled from HD video.
Pixel dimensions — not the DPI label — determine how sharp a print looks.If your source image has fewer pixels than the row you need, three options actually help: pick a lower DPI target (softer but still usable — see the table), print smaller than 8×10, or start from a higher-resolution original if one exists. Simply changing the file's DPI metadata to 300 does not add the missing pixels — see Does Changing DPI Improve Image Quality?
At 300 DPI, an 8×10in photo is exactly 2,400 × 3,000 pixels. At lower DPI targets it needs fewer pixels — see the table above for other common values.
300 DPI is the common standard for photo prints viewed up close, but it's not a strict requirement — many labs accept lower resolutions with some quality tradeoff. Check your specific print lab's minimum before submitting.
Yes, at roughly 250 DPI (2000 ÷ 8 = 250), which is still within a normal photo-print range and will look sharp to most viewers. It falls short of the 300 DPI target but isn't necessarily a problem — see the table above for how DPI drops as pixel count falls.
Upscaling can fill the pixel count, but it estimates detail rather than recovering it — it won't look as sharp as a native-resolution capture. If sharpness at 8×10 matters, a higher-resolution source is the more reliable fix.
No — 8×10 just states the two side lengths. Whether it's portrait (8in wide, 10in tall) or landscape (10in wide, 8in tall) depends on the photo's own orientation and how it's framed.